Adore Delano Age, Net Worth, Weight, Family, Height

Adore Delano is a Singer, Actress, and Drag queen, we are looking Adore Delano Biography & Wiki? She was born on 29 September 1989 Azusa, California, US, America, Adore Delano is a Singer, Actress and Drag queen in America, Adore Delano age 28 years [2017] and Nationality American, 5 feet 8 inches [1.72m] her original height and Her Weight 58-60 Kg Approx.

Adore Delano

Adore Delano

Adore Delano Body Measurements in mystarzone.com Many people ask about Adore Delano Body Measurements & Health, Current her total body measurements are 35-25-35 Inches Body Size, Eyes color, and Hair Color is Black. How tall is Adore Delano? current original height is 5 feet 8 inches [1.72m] and her weight 58-60 Kg Approx.

Peoples Also Looking For Know? Currently used full name? her full name is Adore Delano. Did you know Adore Delano Currently height? Her original height is 5 feet 8 inches [1.72m]. Does Adore Delano smoke? Not Know. Does Adore Delano drink alcohol? Not Know. Adore Delano Net Worth? Her total Net Worth is $ Update Soon. Adore Delano Real Age? 28 year [2017].

Adore Delano Age, Net Worth, Weight, Family, Height

Adore Delano Biography 
Nick NameAdore Delano
ProfessionSinger, Actress, and Drag queen
BirthdayJanuary 12, 1900
Age (as in 2018)28 years [2017]
NationalityAmerican
Height5 feet 8 inches [1.72m]
Weight58-60 Kg Approx
Body Measurements35-25-35

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